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melisa1 [442]
3 years ago
10

Find the value of x

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0

Since 6x and 5x+15 are both 90 degree angles, they equal each other....

6x = 5x+15        (Subtract 5x from both sides to get x alone)

x=15

Sati [7]3 years ago
8 0

Answer:

x = 15

Step-by-step explanation:

Each angle looks to be equal to 90 degrees. To find out what x equals on one side we can do 90/6 and then we get 15 degrees. We can plug 15 into the second equation. (5*15)+15. We also get 90 degrees.

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Answer:

x= 5

Step-by-step explanation:

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3 years ago
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What is the measure of Arc RS?
IRISSAK [1]

Answer:

4.54 inches

Step-by-step explanation:

3 0
3 years ago
What is the greatest common factor and least common multiple of 45 75 and 90?
Ghella [55]
15 and 450 because you divide and multiply until you get the same number
6 0
3 years ago
Simplify the expression. Quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity se
Art [367]

Answer:

D. 1

Step-by-step explanation:

We have the expression, \frac{\csc^{2}x\sec^{2}x}{\sec^{2}x+\csc^{2}x}

We get, eliminating the cosecant function,

\frac{\sec^{2}x}{\frac{\sec^{2}x}{\csc^{2}x}+1}

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,

i.e. \frac{\sec^{2}x}{\frac{\sin^{2}x}{\cos^{2}x}+1}

i.e. \frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}

Since, we know that, \sin^{2}x+\cos^{2}x=1

Thus,

\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}=1

So, after simplifying, we get that the result is 1.

Hence, option D is correct.

3 0
3 years ago
In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF  = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively

Read more about parallelograms at:

brainly.com/question/3050890

#SPJ1

8 0
1 year ago
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