This thing mad hard for no reason

Wht is the answer for 2/3+2/9

garik1379 [7]

2/3 = 6/9 So,

6/9 + 2/9 = 8/9

4 0

3 years ago

Read 2 more answers

Find the area of the regular polygon

olasank [31]

$area = 44.0467 \: cm {}^{2}$

<h3>step by step explanation </h3>

● area of regular polygon Formulas ,

⟹ $a = \frac{l^{2}n}{4tan(\frac{\pi }{n)}}$

● now finding the area of regular polygon,

⟹ $\frac{4 {}^{2} \times 8 }{ 4 \: tan \: \binom{180}{5} }$

⟹ $a = \frac{128}{4 \times 0.7265}$

⟹ $a = 44.0467 \: cm {}^{2}$

Hope it's helps you

4 0

2 years ago

14-2(x+8)=5x-(3x-34)

Scilla [17]

Answer:30=-34

Step-by-step explanation:

First you distribute so 2×X is 2X

2×8 is 16 then you do the other side but you put a one in front of the- so it goes 1 times 3x is 3x and you turn the minus into a plus sign and turn the positive 34 into a negative 34 so -34× 1 is -34 then write that out to look like 14-2X+16= 5X -3X + -34 then you add or subtract the commons which is 14+16= 30 and 5X-3X=2X so now your equation is 30-2x=2X+(-34) then you want to get your X on the same side so you subtract 2X from the right side and the left side then your left 30=-34

4 0

3 years ago

Write the Expression in standard form by expanding and combining like terms 4(8m-7n) +6(3n-4m)

Elina [12.6K]

Standard for is x × 10 ^I
where,
I = indice
10 > x < 0
you cannot write this is standard form with putting in what they stand for. However you can simplify it -

4(8m-7n) +6(3n-4m)
32m - 28n + 18n - 24m
8m - 10n

but hey I am from England do what we call standard form might be different

3 0

3 years ago

According to the University of Nevada Center for Logistics Management, 6% of all mer-

Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z* $\sqrt{\frac{p*(1-p)}{n} } = 0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} }$ ,

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

$H_{0}$ : The proportion of returns at the Houston store is not significantly different from the returns for the nation as a whole.

$H_{a}$ : The proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

The test statistics:

Z = $\frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}$ , where $p_{0}$ is the proportion of nation returns.

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

6 0

3 years ago