Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
Answer:
= 28/3
Step-by-step explanation:
Let's solve your equation step-by-step.
x(3)−(8)(2)−9x+72=0
Step 1: Simplify both sides of the equation.
x(3)−(8)(2)−9x+72=0
3x+−16+−9x+72=0
(3x+−9x)+(−16+72)=0(Combine Like Terms)
−6x+56=0
−6x+56=0
Step 2: Subtract 56 from both sides.
−6x+56−56=0−56
−6x=−56
Step 3: Divide both sides by -6.
−6x
−6
=
−56
−6
x=
28
3
Answer:
x=
28
3
Answer:
10th question ka answer hai OK
Well the first thing you have to do is find out how many times 7 goes into 50 whole. This is 7. So then you take the answer to (7x7) from 50 which gives you one, and put it over 50. This equals 7 + 1/50
Answer:
Step-by-step explanation:
i don't see the thing you put it just shows the question
