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inn [45]
2 years ago
13

9) One baseball team played 34 games throughout their entire season. If this baseball team won 22 of those games, then what perc

entage of their games did they win? Round your answer to the nearest tenth if necessary.
10) At a local department store, slacks have been reduced to $27. This price is at 69.2% of the original price for slacks. Given this, what was the original price of the slacks? Round your answer to the nearest whole number if necessary.​
Mathematics
2 answers:
enot [183]2 years ago
7 0

Answer:

9): 64.7

10): 39$

Step-by-step explanation:

melomori [17]2 years ago
5 0

Answer:

64.7% and $39

Step-by-step explanation:

Question 9:

This means that the baseball team won 22/34 of their games through their entire season. In order to find the percentages of game they won, you divide 22 by 34, which comes out to 0.64705..., which becomes 64.705%. Rounding this to the nearest tenth, this percentage becomes 64.7%. Therefore, the percentage of games their baseball team is 64.7%.

Question 10:

We can represent this problem as the proportion:

\frac{27}{69.2} =\frac{x}{100}

with x being the original price of the slacks.

We cross multiply to solve this equation. 27 times 100 is 2700. Next, we divide 2700 by 69.2, which comes out to 39.017341. Rounding this to the nearest whole number, this value comes out to 39. Therefore, the original price of these slacks is $39.

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What is the equation of the funcion that is graphed as line b?
dolphi86 [110]

Answer:

The equation for b would be y = 1/2x + 1

Step-by-step explanation:

In order to find this, start by finding two points on the line. We'll use (0,1) and (2, 2). From there we start by finding the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (2 - 1)/(2 - 0)

m = 1/2

Now using that, we can plug it, along with a point into point-slope form to get the answer.

y - y1 = m(x - x1)

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y - 1 = 1/2x

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The heights of male students are normally distributed with a mean of 160 cm and a standard deviation
Andreyy89

Answer:

he heights of a group of women are normally distributed with a mean of 170 centimeters and a standard deviation of 10 centimeters. What is the  -score of a member of the group who is 165 centimeters tall?

Step-by-step explanation:

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2 years ago
Alecia earned 48 points on the first quiz and 45 points on the second quiz. What's the percent decrease in her quiz score ?
elixir [45]

Answer:

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3 years ago
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What are the domain and range of f(x) = |x – 3 | + 6? a. Domain: {x | x is all real numbers} Range: {y | y ≥ 6} b. Domain: {x |
just olya [345]

Answer:

a. Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

This is a modular function. All values inside brackets will result in absolute values. In other words, positive numbers.

And we can solve this problem algebraically and graphically.

f(x) = |x-3|+6

There are no restrictions and this function is continuous since we can proceed and take it out the brackets as we'll proceed.

I) y =|x-3|+6

Assuming the symmetrical values for x and -3, i.e. -x and +3

y=-(x-3)+6

y= -x+3+6

y=-x+9

We have a linear equation with no restriction in the Set of Real Numbers. We can choose any value for x, we'll have another for y.

II) Assuming the same values we did in the brackets.

y= x-3 +6

y=x+3

We have another linear equation with no restriction. We can choose any value for x, we'll have another for y.

Finally, we can affirm that the

Domain is  a number that belongs to this Interval: (-∞,∞) inside the Set of Real Numbers or

D={x∈R} even or just like the way it's been written {x|x is all Real Numbers}

Range

The range of function depends on the value set for x since it's the result of y.

But we can say where it starts. And in case of restrictions where it may not continue.

In this case, the range of the function starts at:

y=|x-3|+6

As the range starts at 6, precisely the point (0,6) no matter which value you pick for x. As the function continues with no restriction and goes on and on we can say the Range belongs to this interval [6, ∞) or {y ∈ R /y≥6}

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3 years ago
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