All categories

3 years ago

Which is an equation of the line through (2,-1) and (0,5)

Mathematics

1 answer:

ElenaW [278]3 years ago

4 0

Answer:

$y = mx + c \\ - 1 =2 m + c...(1) \\ 5 = (0)m + c \\ c = 5...(2) \: sub \: in \: (1) \\ - 1 = 2m + 5 \\ m = - 3 \\ y = - 3x + 5$

You might be interested in

HELP! HELP!

alexgriva [62]

Answer:

The answer should be C. By combining like terms you can find the answer. 1.75a+2.75a = 4.5a

2.25b + 1.75b = 4b

2.25c + 1.25c = 3.5c

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A musician has just purchased a theremin — an instrument that can be played by moving your hands in the air. For every 30 centim

Kobotan [32]

Answer:

1665 hertz

Step-by-step explanation:

30 x 3.33 = 1 (1 meter) so 500 x 3.33 = 1665 (1 meter of movement)

8 0

3 years ago

What is the first quartile in this box plot? Enter your answer in the box.

Gemiola [76]

Answer:

I think the first quartile is 30

Step-by-step explanation:

To find the quartiles you would look at the end points of the box.

6 0

3 years ago

Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5

snow_tiger [21]

Answer:

$30x^7y^4u^8$

Step-by-step explanation:

We have been given two expressions $15x^7y^3u^8$ and

$6y^4u^5$

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. $15x^7y^3u^8$ and

$6y^4u^5$

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get $x^7y^4u^8$

Hence required least common multiple is $30x^7y^4u^8$

8 0

3 years ago

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

7 0

3 years ago