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3 years ago

Carol Singer had a previous balance of $557.83 in her checking account. She

Mathematics

1 answer:

mamaluj [8]3 years ago

7 0

Answer:

Step-by-step explanation:

Starting balance is $557.83.

Deposited checks adds to the beginning balance

557.83 + 882.84 = 1440.67

Cash withdraw subtracts from the new balance

1440.67 - 325 = 1115.67

Checks paid by the bank subtract from the new balance

1115.67 - 617.77 = 497.90

Interest gets added onto the new balance

497.90 + 1.15 = 499.05

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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function

Aloiza [94]

The ball's maximum height is 30.25 feet.

<h3>What is quadratic equation?</h3>

A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.

Given:

h= -16t²+36t+10

Differentiate w.r.t. 't',

h' = -32t+36

When h=0, that will be the maximum height

32t= 36

t= 9/8

t= 1.125 sec.

So, The maximum height is

h(1.123)= -16(1.125)² + 36*1.125+10

h(1.125) = 30.25 feet.

Learn more about this concept here:

brainly.com/question/10335037

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5 0

2 years ago

Need help with this answer plz help

jeyben [28]

It would be H because 13 has no factors other than 1, and 13.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$