1) x < 4 the answer is <span> Option C: x E(-infinity,4) (it is strict)
2) </span>2x +6 < 8, and <span>2x < 8 - 6 = 2, and x<2/2=1
the answer is </span>
<span>D. x E (-infinity, 1)
</span>3) <span>X greater than or equal to 8 and x < - 4
</span>X greater than 8 means x ≥ 8
so we have x ≥ 8 and <span> x < - 4
so the answer is </span>
<span>B. x E (-4,8]
</span> 4)
7 > x + 6 or x -2 greater than or equal to 3,
<span>7 > x + 6 or x -2 ≥ 3
</span>
<span>7 -6> x, and 1>x
</span>
x -2 ≥ 3 x<span>≥ 3+2=5
finally
</span>x<1 and x≥5
the answer is
<span>C.x E (1,5]
5)
</span>
|x+3| > 12,
|x+3| = { -(x+3) if <span>x+3<0 or </span><span>(x+3) if </span><span>x+3>0}</span>
so, it is -(x+3)>12 is equivalent to (x+3)< -12 or (x+3)>12
the answer is
<span>B. x + 3 > 12 or x + 3 <-12</span>
Lowest to highest in order:
-10, -2, 0, 3, 4, 6
Answer:
z=-58 bc 13-71= -58
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
(x-4)^2 = x^2 -4x -4x + (-4)*(-4)
= x^2-8x+16 as required
It’a the third , and can I have the brainliest too
