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Aleonysh [2.5K]
2 years ago
9

14 + 35 = 7(2 + ___)

Mathematics
2 answers:
murzikaleks [220]2 years ago
5 0

Answer:

x=5

Step-by-step explanation:

14+35=7(2+x)

14+35=49

7*2 &7*x= 14+7x

49= 14+7x (

49 (-14)= 14 (-14) + 7x

35=7x

35/7=5

5=x

xz_007 [3.2K]2 years ago
3 0

Answer:

5

Step-by-step explanation:

Hope this helps and pls mark me brainliest:)

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What is a formula for the nth term of the given sequence? 12, 6, 3
AURORKA [14]

Answer:

I think it is dividing the numbers by 2

4 0
2 years ago
Sebastian measures a line to be 9.2 inches long. if the actual length of the line is 19.5 inches, then what was the percent erro
seraphim [82]

Answer:

47%

Step-by-step explanation:

9.2/19.5=0.47179

the number in the tenth place is 7 and It can´t be changed because 1 isn´t 5 or it also isn´t greater than 5.

4 0
3 years ago
A building with a cost of $1,800,000 has an estimated residual value of $125,000, has an estimated useful life of 40 years, and
nika2105 [10]

Answer:

$41,875

<u>Extra</u>

a. $17,250 [($780,000 – $90,000) ÷ 40]

b. $366,000 [$780,000 – ($17,250 × 24 yrs.)]

c. $29,600 [($366,000 – $70,000) ÷ 10 yrs.]

Step-by-step explanation:

Step 1: Determine the cost of the asset

1,800,000

Step 2: Subtract the estimated salvage value of the asset from the cost of the asset to get the total depreciable amount

1,800,000 - 125,000

Step 3: Determine the useful life of the asset

40

Step 4: Divide the sum of step (2) by the number arrived at in step (3) to get the annual depreciation amount

$41,875

5 0
3 years ago
Manuel made 5 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 5 necklaces
valentinak56 [21]

Answer:

2.3

Step-by-step explanation:

Step 1: Divide 30.50 by 5 to get that each necklaces costs 6.1.

Step 2: Subtract 6.1 (cost for 1 necklace) and 3.80 (price of beads)

Your answer is 2.3! Please mark this as brainliest

4 0
3 years ago
Read 2 more answers
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\frac{x(x - 1)}{(x + 1)(x - 1)} - \frac{1(x + 1)}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x}{(x + 1)(x - 1)} - \frac{x + 1}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x + x + 1 + 2x}{(x + 1)(x - 1)}
\frac{x^{2} + 2x + 1}{(x + 1)(x - 1)}
\frac{(x + 1)(x + 1)}{(x + 1)(x - 1)}
\frac{(x + 1)^{2}}{(x + 1)(x - 1)}
\frac{x + 1}{x - 1}
4 0
3 years ago
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