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3 years ago

What -45 divided by 75

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

-0.6

Step-by-step explanation:

The answer is negative because -45 was a negative number.

I didn't explain that very well :|

Hope I helped :)

Can I get Brainliest anyway, even though I did a terrible job explaining? .-.

vodomira [7]3 years ago

7 0

The answer is -0.6 or -3/5

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WILL GIVE BRAINLIEST ONLY IF ANSWER IS CORRECT!!! WRONG ANSWERS JUST FOR POINTS WILL BE REPORTED!!!!!!!!!!!

weeeeeb [17]

Answer:

r=14 in

Step-by-step explanation:

The volume of a cylinder is given by:

$v = \pi \times {r}^{2} \times h$

So,

$r = \sqrt{ \frac{v}{\pi \times h} } = \sqrt{ \frac{196 \times \pi}{\pi \times 1} } = \sqrt{196} = 14$

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3 years ago

Read 2 more answers

Can you help me find the value of x and y for both

Nastasia [14]

Answer:

For the First Question:

x = 61

y = 61

For the Second Question:

x = 12

y = 7

Step-by-step explanation:

Second question:

96 = 11y + 19

11y = 77

y = 7

96 = 8x

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3 years ago

PLS HELP ME PLS I WILL MARK BRAINLIEST PLS

Vesnalui [34]

Answer:

AB = 25

Step-by-step explanation:

First things first, we know that these triangles are similar. Now let's find BC using the Pythagorean Theorem. BC = $5\sqrt5$ , this side is similar to the 5 side of the smaller triangle. That means each side of the larger triangle $\sqrt5$ times larger than the corresponding side on the small triangle. That means AB is $\sqrt5$ times larger than BC as well. So multiply BC by $\sqrt5$ get us the answer.

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3 years ago

(10-1)(10-2)(10-3)(10-10)

Vinvika [58]

Answer:

Step-by-step explanation:

$(10 - 1)(10 - 2)(10 - 3)(10 - 10)$

10-10 is zero and Anything multiply by a factor of 0 equal 0 so

0 is the answer

4 0

3 years ago

As the limit of x goes to 3 from the left find the limit of (x/ sqrt x^2 -9)

Dimas [21]

$\displaystyle\lim_{x\to3^-}\frac x{\sqrt{x^2-9}}=\lim_{x\to3^-}\frac x{\sqrt{x^2}\sqrt{1-\frac9{x^2}}}=\lim_{x\to3^-}\frac x{|x|\sqrt{1-\frac9{x^2}}}$

Since $x>0$ , you have $|x|=x$ and the limand reduces to

$\displaystyle\lim_{x\to3^-}\frac1{\sqrt{1-\frac9{x^2}}}$

For $x>3$ , you have $\sqrt{1-\frac9{x^2}}>0$ since $\dfrac9{x^2}$ will always be smaller than 1, which means $\dfrac1{\sqrt{1-\frac9{x^2}}}\to+\infty$

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4 years ago