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Brut [27]
3 years ago
14

Convert into standard notation

Mathematics
2 answers:
kobusy [5.1K]3 years ago
5 0

Answer:

9) 3924000000000000

10) 92000000000000000

11) 0.004391

12) 0.0006825

Misha Larkins [42]3 years ago
4 0

Answer:

I have no idea waht your talking about.

Please explain.

Step-by-step explanation:

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If m and n are zeros of ax2-5x+c, find a and c when m+n=mn=10
kompoz [17]
ax^2+bx+c=0
if m and n are zeros, then:
m+n=\dfrac{-b}{a}\ and\ mn=\dfrac{c}{a}
We have:
ax^2-5x+c=0\to b=-5\\\\m+n=mn=10
substitute
m+n=\dfrac{-(-5)}{a};\ mn=\dfrac{c}{a}\\\\ \left\{\begin{array}{ccc}\dfrac{5}{a}=10&\to a=\dfrac{1}{2}\\\\\dfrac{c}{a}=10\end{array}\right
substitute the value of a to the second equation:
\dfrac{c}{\frac{1}{2}}=10\\\\2c=10\ \ \ |:2\\\\c=5

Answer:  \boxed{a=\dfrac{1}{2};\ c=5}


6 0
3 years ago
True or false: the range of y=arcsinx is [-pi/2, pi/2]
balandron [24]

True.


The range for arctan is all the valid Y-Values, and if you take a look at the graph you can see it caps out at pi/2 and -pi/2 for y values.


P.S. pi/2 = 1.57......



7 0
4 years ago
Read 2 more answers
Make sure and read this carefully!
olchik [2.2K]

Answer:

yo mama read this carefully-

Step-by-step explanation:

7 0
3 years ago
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What is the measure of the hypotenuse?
SVETLANKA909090 [29]

Answer:

To find the hypotenuse you need to use the Pythagorean Theorem which is

a^2+b^2=c^2

Where a and b are your two sides and c is your diagonal line

So you want to plug the numbers in for the right variables

5^2+12^2=c^2

We want to find what c equals so we are first gonna simplify

25+144=c^2

we take 5^2=25, and 12^2=144, then we add them together 25+144=169

169=c^2 now you want to take 169 and square root it because the opposite of squaring is taking it by the root square

The square root of 169=13

Your hypotenuse is 13

Hope this helps ;)

4 0
3 years ago
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Nate and his sister Natalie are walking around the track at school and they’re walking at a steady rate. Nate walks 5 feet in 2
lutik1710 [3]
 Nate     Natalie
  5_2        2_2
10_4        4_4
15_6        6_6

Natalie walked 6 feet
7 0
3 years ago
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