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Nataly_w [17]
3 years ago
6

Which are equivalent expressions to 4x+8 (select all that apply)

Mathematics
2 answers:
mojhsa [17]3 years ago
4 0
Lets say that x=2(doesn't actually equal 2 is just plugging in a random number to make it easier)

4x+8=4*2+8=16

A is incorrect 4(x+8)=4(2+8)=40 

B is correct  4(x+2)=4(2+2)=16

C is correct (8x+16)/2=(8*2+16)/2=16

D is correct 8+4x=8+4*2=16

E is incorrect (8x+8)/2=(8*2+8)/2=12

So the correct answers are: B C D

Ksju [112]3 years ago
3 0
C, b, and d
....................................
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Answer:

CV=0.2 ---- dataset 1

CV = 7.2 --- dataset 2

Step-by-step explanation:

Given

A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,33100

B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11

Required

The coefficient of variation of each

<u>Dataset A</u>

Calculate the mean

\mu = \frac{\sum x}{n}

\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}\mu = \frac{418900}{14}

\mu = 29921.43

Next, calculate the standard deviation using:

\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}

So, we have:

\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}

\sigma= \sqrt{\frac{487723571.42857}{14}}

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\sigma= 5902.32

So, the coefficient of variation is:

CV=\frac{\sigma}{\mu}

CV=\frac{5902.32}{29921.43}

CV=0.2 --- approximated

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Calculate the mean

\mu = \frac{\sum x}{n}

\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}

\mu = \frac{46.79}{11}

\mu = 4.25

Next, calculate the standard deviation using:

\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}

\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}

\sigma = \sqrt{\frac{3.859}{11}}

\sigma = \sqrt{0.35081818181}

\sigma = 0.593

So, the coefficient of variation is:

CV=\frac{\sigma}{\mu}

CV = \frac{4.25}{0.5903}

CV = 7.2 -- approximated

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Answer:

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