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Free_Kalibri [48]
2 years ago
10

What is -3\4 + (-3\8)

Mathematics
1 answer:
Alexus [3.1K]2 years ago
3 0
The answer is -9/8, hope this helps!
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The figure is made up of 3 semicircles. Find its perimeter in terms of pi.
icang [17]

Answer:

The answer is 20pi

Step-by-step explanation:

perimeter of a semicircle = pi* radius

perimeter of first semicircle = 5.pi

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total perimeter = 5pi +5pi + 10pi

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The base of a triangle exceeds the height by 3 cm if the area is 170 cm² what is the length of the base and the height of the tr
Strike441 [17]

Hey there!!

How do we find the area of a triangle?

Ans - Formula = ( 1 / 2 ) ( base ) ( height )

In the question, it states the base exceeds the height by 3 cm

Let's take the height as ' x '

The, the base of the triangle would be ' x + 3 '

It's area = 170 cm²

Let' get this into an equation :

( 1/2 ) ( x ) ( x + 3 ) = 170

... ( x / 2 ) ( x + 3 ) = 170

... ( x² + 3x / 2 ) = 170

Multiplying by 2 on both sides

... x² + 3x = 340

Subtract 340 on both sides

... x² + 3x - 340 = 0

We can write this as

... x² - 17x + 20x - 340 = 0

... x ( x - 17 ) + 20 ( x - 17 ) = 0

... ( x + 20 ) = 0

... ( x - 17 ) = 0

... x = -20

... x = 17

As the value can not be in negatives, we take x as 17

The value of height = 17 cm

The value of the base = 20 cm

Hope my answer helps!!


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any other info?

Step-by-step explanation:

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Solve the proportion
mario62 [17]

Answer:

\boxed{\sf x = 5}

Step-by-step explanation:

\sf Solve  \: for  \: x  \: over  \: the  \: real \:  numbers:  \\ \sf \implies  \frac{2}{x - 3}   =  \frac{5}{x}  \\  \\  \sf Take  \: the \:  reciprocal  \: of  \: both \:  sides:  \\ \sf \implies  \frac{x - 3}{2}  =  \frac{x}{5}  \\  \\  \sf Expand  \: out \:  terms \:  of \:  the \:  left  \: hand \:  side:  \\  \\ \sf \implies \frac{x}{2}  -  \frac{3}{2}  =  \frac{x}{5}  \\  \\  \sf Subtract \:  \frac{x}{5}   -  \frac{3}{2}  \: from  \: both  \: sides: \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} - ( \frac{x}{5}   -  \frac{3}{2} ) =  \frac{x}{5} - ( \frac{x}{5}  -  \frac{3}{2} ) \\  \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} -  \frac{x}{5}    +   \frac{3}{2} =  \frac{x}{5} -  \frac{x}{5}  +  \frac{3}{2}  \\  \\  \sf \frac{x}{5}  -  \frac{x}{5}  = 0 :  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  -  \frac{3}{2}  +  \frac{3}{2}  =  \frac{3}{2}  \\  \\  \sf  \frac{3}{2}   -   \frac{3}{2}   = 0:  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  =  \frac{3}{2}   \\  \\ \sf \frac{x}{2}  -  \frac{x}{5} =  \frac{5x - 2x}{10}  =  \frac{3x}{10} :  \\   \sf \implies \frac{3x}{10}  =  \frac{3}{2}   \\  \\ \sf Multiply \:  both  \: sides \:  by \:  \frac{10}{3}  : \\   \sf \implies \frac{3x}{10}  \times  \frac{10}{3}  =  \frac{3}{2 }  \times  \frac{10}{3}   \\  \\ \sf \frac{3x}{10}  \times  \frac{10}{3}  =   \cancel{\frac{3}{10} } \times( x) \times  \cancel{ \frac{10}{3} } = x :  \\  \sf \implies x =  \frac{3}{2}  \times  \frac{10}{3} \\  \\   \sf  \frac{3}{2}  \times  \frac{10}{3}  = \cancel{ \frac{3}{2} }  \times \cancel{ \frac{3}{2} }  \times 5 :   \\ \sf \implies x = 5

8 0
3 years ago
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