Question

If any of you know how to do this pls help :)))

Answer 1

Answer:

y=3/5,6

Step-by-step explanation:

(5y-3)(y-6)=0

5y-3=0 y-6=0

y=3/5 y=6

Find all the values that make it true

Hope this helps! :)

Answer 2

Answer:

y=3/5,6

Step-by-step explanation:

Split the second term in 5{y}^{2}-33y+185y2−33y+18 into two terms.

5{y}^{2}-3y-30y+18=05y2−3y−30y+18=0

2

 

Factor out common terms in the first two terms, then in the last two terms.

y(5y-3)-6(5y-3)=0y(5y−3)−6(5y−3)=0

3

 

Factor out the common term 5y-35y−3.

(5y-3)(y-6)=0(5y−3)(y−6)=0

4

 



Solve for yy.

y=\frac{3}{5},6y=53,6