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Marta_Voda [28]
3 years ago
12

If any of you know how to do this pls help :)))

Mathematics
2 answers:
Korvikt [17]3 years ago
5 0

Answer:

y=3/5,6

Step-by-step explanation:

(5y-3)(y-6)=0

5y-3=0 y-6=0

y=3/5 y=6

Find all the values that make it true

Hope this helps! :)

andreev551 [17]3 years ago
3 0

Answer:

y=3/5,6

Step-by-step explanation:

Split the second term in 5{y}^{2}-33y+185y2−33y+18 into two terms.

5{y}^{2}-3y-30y+18=05y2−3y−30y+18=0

2

 

Factor out common terms in the first two terms, then in the last two terms.

y(5y-3)-6(5y-3)=0y(5y−3)−6(5y−3)=0

3

 

Factor out the common term 5y-35y−3.

(5y-3)(y-6)=0(5y−3)(y−6)=0

4

 



Solve for yy.

y=\frac{3}{5},6y=53,6

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3 years ago
What is 1 divided by 5^-2? Please give clear explanation. thanks.
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1 / 5^-2

First, let's work out the denominator.
5^ -2 = 1/25. When an exponent is negative, it means to put a 1 over the product. Like we did earlier.

Now we have 1 / (1/25). 

1 / (1/25)
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Help answer asap pls ---------
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Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: \sqrt{8 - (-1)} = 2(-1)+d. On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: \sqrt{9} = d-2. We know that \sqrt{9} = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!

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