Question

What two numbers have a difference of 5 and a product of 3.36

Answer 1

X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula


for
ay^2+by+c=0
$y= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$
for 1y^2+5y-3.36
$y= \frac{-5+/- \sqrt{5^2-4(1)(-3.36)} }{2(1)}$
$y= \frac{-5+/- \sqrt{25+13.44} }{2}$
$y= \frac{-5+/- \sqrt{38.44} }{2}$
$y= \frac{-5+/- 6.2}{2}$
y=-2.5+/-3.1
y=5.6 or 0.6
sub back

x=y+5
so
x=10.6 or 5.6


the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer

answer is 0.6 and 5.6