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4 years ago

Use the commutative law of MULTIPLICATION to write an equivalent expression. 9(x+5)

1 answer:

3 0

The commutative property of multiplication is ab=ba
so
9(x+5)=(x+5)9
(note, some people on this site like to write x2 for x² but that's not how you math correctly., (x+5)9 doesn't mean (x+5)⁹, it means (x+5) times 9)

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I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

4 years ago

Please help! Simplify the rational expression. State any restrictions on the variable.

alukav5142 [94]

Step-by-step explanation:

t^2-4xt-12/t-8

= -(t^2-4-6)/4

= -t^2+4+6/4

=<u> -t^2+6</u>

6 0

3 years ago

I need help with this.

leonid [27]

You are basically just comparing the ratios (the ratios will have to be the same for both for it to be the correct answer)
so for choice A you would do:
116.5cm:845km =0.14
174cm:1160km=0.15
these are not equal so it would not be correct

the correct answer would be B because:
42.25cm:845km=.05
58cm:1160km=.05

5 0

4 years ago

Please show how to do this

myrzilka [38]

Answer:

i dont know

Step-by-step explanation:

5 0

3 years ago

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1/2-1/4<br><br> help?:) uhhhh thankssss

sertanlavr [38]