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Diano4ka-milaya [45]
2 years ago
15

A flat fee of $15.25 plus $3.45 per pound of supplies ordered is added to the bill to cover the shipping cost.The teacher budget

s $49.75 for the shipping cost.Which list of values best represents the entire domain for shipping, f(x), as a function of the number of whole pounds of school supplies the teacher can order, x?
Mathematics
1 answer:
likoan [24]2 years ago
8 0

The domain of a function is the set of possible <em>input value</em>, the function can take.

The domain is [0,10]

The given parameters are:

Flat\ Fee = 15.25

Rate = 3.45

So, the function f(x) is:

f(x) = Flat\ Fee + Rate \times x

f(x) = 15.25 + 3.45 \times x

f(x) = 15.25 + 3.45x

Because x represents the <em>number of orders</em>, the value of x cannot be negative.

The teacher budgets $49.75.

This means that: f(x) = 49.75

So, we have:

49.75 = 15.25 + 3.45x

Collect like terms

49.75 - 15.25 = 3.45x

34.5 = 3.45x

Divide both sides by 3.45

10 = x

Rewrite as

x = 10

Hence, the domain is [0,10]

Read more about domains at:

brainly.com/question/21853810

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Answer:

41ft is your answer

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There are 4 cats in a street,Five more come . How many cats are in a street ?
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7h + 4 &gt; 5 – 5h solve the inequality
loris [4]

Step-by-step explanation:

7h + 4 > 5 - 5h

7h + 5h > 5 - 4

12h > 1

h > 1/12

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2 years ago
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Given that g(x)=x-3/x+4 find each of the following.
maks197457 [2]

Given that the function g(x)=x-3/x+4, the evaluation gives:

  1. g(9) = 6/13.
  2. g(3) = 0.
  3. g(-4) = undefined.
  4. g(-18.75) = 1.07.
  5. g(x+h) = x+h-3/x+h+4

<h3>How to evaluate the function?</h3>

In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:

When g = 9, we have:

g(x)=x-3/x+4

g(9) = 9-3/9+4

g(9) = 6/13.

When g = 3, we have:

g(x)=x-3/x+4

g(3) = 3-3/3+4

g(3) = 0/13.

g(3) = 0.

When g = -4, we have:

g(x)=x-3/x+4

g(-4) = -4-3/-4+4

g(-4) = -1/0.

g(-4) = undefined.

When g = -18.75, we have:

g(x)=x-3/x+4

g(-18.75) = -18.75-3/-18.75+4

g(-18.75) = -15.75/-14.75.

g(-18.75) = 1.07.

When g = x+h, we have:

g(x)=x-3/x+4

g(x+h) = x+h-3/x+h+4

Read more on function here: brainly.com/question/17610972

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8 0
2 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Rudik [331]
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section.  That's
         (change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change =            (change in the value of the function) / (size of the section) = 5/1  =  5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change =           (change in the value of the function) / (size of the section) = 5/1  =  5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0
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