A flat fee of $15.25 plus $3.45 per pound of supplies ordered is added to the bill to cover the shipping cost.The teacher budget
1 answer:
The domain of a function is the set of possible <em>input value</em>, the function can take.
The domain is [0,10]
The given parameters are:
So, the function f(x) is:
Because x represents the <em>number of orders</em>, the value of x cannot be negative.
The teacher budgets $49.75.
This means that: f(x) = 49.75
So, we have:
Collect like terms
Divide both sides by 3.45
Rewrite as
Hence, the domain is [0,10]
Read more about domains at:
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Answer:
w =
Step-by-step explanation:
p = 2l + 2w Subtract 2l from both sides of the equation
p - 2l = 2p Divide both sides by 2
= w
How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.
#3
Let's start with sin here. Therefore, because sin is y/r, r =
and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.
cos =
#4
Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = . Now, to find csc, we have to do r/y.
csc =
The pythagorean identities are
sin^2 + cos^2 = 1,
1 + cot^2 = csc^2,
tan^2 + 1 = sec^2.
#5
Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.
sin^2 + (-3/4)^2 = 1
sin^2 + 9/16 = 1
sin^2 = 7/16
sin = =
Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.
tan^2 + 1 = (-4/3)^2
tan^2 + 1 = 16/9
tan^2 = 7/9
tan = -
#6
Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.
1 + cot^2 =
1 + cot^2 = 6/4
cot^2 = 2/4
cot =
tan =
Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.
+ 1 = sec^2
4/2 + 1 = sec^2
2 + 1 = sec^2
sec^2 = 3
sec = -
cos =
Hope this helps!! :)