The length of the function y = 3x over the given interval [0, 2] is 3.2 units
For given question,
We have been given a function y = 3x
We need to find the length of the function on the interval x = 0 to x = 2.
Let f(x) = 3x where f(x) = y
We have f'(x) = 3, so [f'(x)]² = 9.
Then the arc length is given by,
![\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7B%5Csqrt%7B1%2B%5Bf%27%28x%29%5D%5E2%7D%20%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D%20%5Cint%5Climits%5E2_0%20%7B%5Csqrt%7B1%2B9%7D%20%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Csqrt%7B10%7D%5C%5C%5C%5C%20%3D3.2)
This means, the arc length is 3.2 units.
Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units
Learn more about the arc length here:
brainly.com/question/10729208
#SPJ4
Starting with x=1, subtract 1 from each side,
(x-1)=0
Our polynomial will have multiplicity of 2 for this particular zero,
(x-1)(x-1)
and do similar with the x=-4, add 4 to each side,
(x+4)=0
So our final result is: (x-1)(x-1)(x+4)
Expand out the brackets if you need this in standard form.
Get your answers from yahoo. Answers. it helps
AC and AB are tangents to circle O, meaning that the angles C and B are right angles of 90 degrees. Since a quadrilateral's internal angles must sum up to 360 degrees, this means that A + B + C + O = 360
70 + 90 + 90 + O = 360
O = 110 degrees.
