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mezya [45]
3 years ago
7

A scientist uses a submarine to study ocean life. She begins at sea level, which is at an elevation of 0 feet She travels straig

ht down for 90 seconds at a speed of 3.5 feet per second. She then travels directly up for 30 seconds at a speed of 2.2 feet per second. After this 120-second period, how much time, in seconds, will it take for the scientist to travel back to sea level at the submarine’s maximum speed of 4.8 feet per second? Round your answer to the nearest tenth of a second.
Mathematics
1 answer:
KatRina [158]3 years ago
5 0
Distance = speed*time
 1st              = 90*3.5
               = 315ft
2nd         = 30*2.2
               = 66ft
0-315+66= -315+66= -249ft
(249/4.8)= 51.875 = 51.86 seconds
Hope this helps.
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2 terms

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Answer:

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The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

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Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

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0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

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