To solve this equation you can plug in these numbers into the equations, so for example you can that the equation a-3b=9 and the points are (-9,-6). you would then insert the numbers so you would have the equation (-9)-3(-6)=9. simplify -9+18=9 and there you have it, the answer is (-9,-6)
154
Subtract $1060 from $5680 to get $4620 > divide $4620 by $30 to get 154 > 154 students can attend
Answer:
2 terms
Step-by-step explanation:
Terms are nothing but the mixtures of co-effecients and their variables..
Here, 9a is one term while 11p is the other
Answer:
6 hours
Step-by-step explanation:
Suppose Madison spent x hours on her social project,
then the number of hours spent on other project will be 1/3 of x=x/3
Total hours spend on all projects will be the addition of hours spent on social project and hour spent on other project, i.e
x + x/3 = 4x/3
It si given that this is 8 hours, therefore
4x/3=8
Multiplying both sides by 3:
4x=24
Dividing across board by 4:
x= 6 hours
Answer:
0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.
The sketch is drawn at the end.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 0°C and a standard deviation of 1.00°C.
This means that 
Find the probability that a randomly selected thermometer reads between −2.23 and −1.69
This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.
X = -1.69



has a p-value of 0.0455
X = -2.23



has a p-value of 0.0129
0.0455 - 0.0129 = 0.0326
0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.
Sketch: