y = total cost used.
x = additional minutes
y = $49.95 + $0.15x
$61.20 = $49.95 + $0.15x. Subtract the $49.95 from each side.
$11.25 = $0.15x. Divide each side by $0.15
75 = x.
Michael used 75 additional minutes.
Answer:
Derivative: P’(x) = 200 - 2x
If P’(x) = 0 , x = 100
Therefore P’ is positive and P increases until x = 100
So the maximum units to maximize profits is 100 units
And for 100 units the profit in dollar is:
20000 - 10000 = 10000
10000 dollars
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒
Now let
∵
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
Answer:
About 4 times per year.
Step-by-step explanation:
Research studies online.