Answer:
2 ( x+3) (x+1)
Step-by-step explanation:
2x^2+8x+6
Factor out a 2
2(x^2 +4x+3)
Factor in side the parentheses
What multiply to 3 and adds to 4 (3(1=3 3+1 =4)
2 ( x+3) (x+1)
Answer:
First, you get both of them with same denominator:
3/7 and 2/3 => 9/21 and 14/21, however, there are only 4 rational numbers between 9/21 and 14/21.
The solution is that you can raise the denominator 2 times:
9/21 and 14/21 => 18/42 and 28/42
Now you can select : 19/42, 20/42, 21/42, 22/42, 23/42. They are a group of 5 rational numbers you are looking for.
Let the regular price be p. Then the new price, after a 35% markdown, is 0.65p.
Mult. $3.29 by 0.65, Result: $2.14. No match here.
Mult. $4.19 by 0.65. Result: $2.72. We've got a match here!
Mult. $2.79 by .65. Result: $1.81. No match here.
Mult. $3.09 by .65. Result: $2.01. Match!
And so on.
Answer:
no
Step-by-step explanation:
2(3)+2=8
6+2=8
-x+3y=4
-(3)+3(2)=4
-3+6=4
3 does not equal 4
Y = 3x + 3
y = x - 1
As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.
3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2
Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.
y = x - 1
y = -2 - 1
y = -3
The final step is to check all work by plugging both x- and y-values back into both equations.
y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3 -- This is true
y = x - 1
-3 = -2 - 1
-3 = -3 -- This is true.
Answer:
(-2, -3)
