Answer:
The correct answer to the following question will be the Group Policy Container (GPC).
Explanation:
Group Policy Container (GPC) : An active directive container that contains properties of GPO (such as the setting of GPO, it's component settings), is known as Group Policy Container.
There are two locations where GPO stores its configuration information :
- Group Policy Container (GPC).
- Group Policy Template (GPT).
Spoofing is<span> an attempt to gain access to a network by posing as an authorized user in order to find sensitive information, such as passwords and credit card information. </span>
Answer : Encoding
Explanation : Encoding refers to correctly coding the message so that the receiver gets the clear message without feating any misunderstanding.
Answer:
C)An error message is issued.
Explanation:
If we try to open a file for reading when that file does not exist, we will get an error message.
For example, in Java we will encounter a FileNotFoundException as in the code below:
try {
FileInputStream fis = new FileInputStream("myFile.txt");
DataInputStream dis = new DataInputStream(fis);
BufferedReader br = new BufferedReader(new InputStreamReader(dis));
String str = null;
while ((str = br.readLine()) != null) {
System.err.println(str);
}
} catch (FileNotFoundException e) {
e.printStackTrace();
}
If the file myFile.txt does not exist we can expect to see an exception stack trace corresponding to FileNotFoundException.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
