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brilliants [131]
3 years ago
12

Help me I really dont understand this is a free 20 points

Mathematics
2 answers:
Andreyy893 years ago
8 0

Answer:

C

Step-by-step explanation:

kherson [118]3 years ago
3 0

Answer: its b

Step-by-step explanation:

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What is the slope of a line passing through (-3,-7) and (1,4)
Leona [35]

solution,

slope(m) = y2-y1/ x2-x1

= 4+7/1+3

=11/4

I hope this is correct, the formula can be wrong so pls double check if u have formula.

4 0
3 years ago
Which function is undefined for x=0
maria [59]

Answer:

of course 0

Step-by-step explanation:

because it doesn't have any value in its first equation

3 0
2 years ago
Read 2 more answers
Pls help the first one is done but use that one to do the other one
dexar [7]

Answer:

I got 107 ft. ² and D.........

5 0
3 years ago
Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0
3 years ago
A group consists of fivefive men and fivefive women. ThreeThree people are selected to attend a conference. a. In how many ways
dem82 [27]

a).  Three people can be selected from a group of ten in

(10 · 9 · 8) = <em>720 ways</em>.

(But every group of 3 different people can be selected in 6 different ways.  So there are actually only (720/6) = 120 different groups of 3 different people.)

b).  Three women can be selected from a group of five women in

(5 · 4 · 3) = <em>60 ways</em>.

(But every group of 3 different women can be selected in 6 different ways.  So there are actually only (60/6) = 10 different groups of 3 different women.)

   

c).  Start with 3 men and 3 women.

The probability of the first selection being a woman is (3/6) = 50% .

Then there are 3 men and 2 women.

The probability of the 2nd selection being a woman is (2/5) = 40% .

Then there are 3 men and 1 woman.

The probability of the 3rd selection being a woman is (1/4) = 25% .

The probability of all 3 selections being women is

(50% ·40% ·25%) = (0.5 ·0.4 ·0.25) = <em>0.05</em>

The probability that the selected group will consist of all women is <em> 5%</em> .

8 0
3 years ago
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