A translation is a rigid transformation, which means angle measures and distances from two points do not change.
Polygon ABCDEF is congruent to polygon A'B'C'D'E'F'
DE = D'E' = 7
Answer:
two solutions
x1=-8 , x2=2
Step-by-step explanation:
x^{2}+6x-16=0 move constant to the right
x^{2}=6x=16 add (
) to both sides of question
x^{2}+6x+(
)=16+(
)
x^{2}=6x+(
)=16+(
)
using a^{2}+2ab+b^{2}=(a+b)^{2}, factor the expression
![(x+\frac{6}{2} ^{2}=16+(\frac{6}{2})^{2}](https://tex.z-dn.net/?f=%28x%2B%5Cfrac%7B6%7D%7B2%7D%20%5E%7B2%7D%3D16%2B%28%5Cfrac%7B6%7D%7B2%7D%29%5E%7B2%7D)
[tex](x+\frac{6}{2} ^{2}=25
reduce the fraction with 2
(x+3)^{2}=25
solve for x
the get final solution of x= -8 and x= 2
The domain is the whole set of x values, so the domain would go from -infinity to positive infinity. The vertex would be (-5,0) because that is the lowest point on the graph. The Range would include -5 and go up to infinity.