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densk [106]
4 years ago
13

Given: 3(x-4)=2x+7 Prove: x=19 PROOF: StatementsReasons

Mathematics
1 answer:
Musya8 [376]4 years ago
4 0
Hey !

3(x - 4) = 2x + 7 \\ \\ 3x - 12 = 2x + 7 \\ \\ 3x - 2x = 7 + 12 \\ \\ x = 19 \: \: \: \: \: \: \: Ans.

Hope it helps you :)
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Pls help for 10 points plssss
WITCHER [35]
(x+9)(x+8) = x^2 +17x + 72
(x- 7)(x+8) = x^2 + x - 72
(x- 5)(x- 6) = x^2 -11x + 30
(2x + 3)(3x+2) = 6x^2 + 13x +6
(5x - 4)(2x-5) = 10x^2 - 33x + 20
(x-4)^2 =  x^2 -8x + 16
(2x+1)^2 = 4x^2 +4x + 1
(4x+3)(4x-3) = 16x^2 - 9
5 0
4 years ago
I need help fast please
marta [7]

Step-by-step explanation:

(-)(-) = +

-  \frac{3}{5}  +  \frac{5}{9}

-   \frac{27}{45}  +  \frac{25}{45}

- \frac{2}{45}

8 0
3 years ago
Given: Quadrilateral ABCD is inscribed in circle O.
Airida [17]
1. Quadrilateral ABCD is inscribed in circle O
A quadrilateral is a four sided figure, in this case ABCD is a cyclic quadrilateral such that all its vertices touches the circumference of the circle.
A cyclic quadrilateral is a four sided figure with all its vertices touching the circumference of a circle.

2. mBCD = 2 (m∠A) = Inscribed Angle Theorem
An inscribed angle is an angle with its vertex on the circle, formed by two intersecting chords. 
Such that Inscribed angle = 1/2 Intercepted Arc
In this case the inscribed angle is m∠A and the intercepted arc is MBCD
Therefore; m∠A = 1/2 mBCD

4. The sum of arcs that make up a circle is 360
Therefore; mBCD + mDAB = 360°
The circles is made up of arc BCD and arc DAB, therefore the sum angle of the arcs is equivalent to 360°

5. 2(m∠A + 2(m∠C) = 360; this is substitution property
From step 4 we stated that mBCD +mDAB = 360
but from the inscribed angle theorem;
mBCD= 2 (m∠A) and mDAB = 2(m∠C)
Therefore; substituting in the equation in step 4 we get;
2(m∠A) + 2(m∠C) = 360

6 0
4 years ago
Read 2 more answers
PLS HELP ! Will give brainliest!
Rasek [7]

Given:

The quadratic equation is :

16x^2-20x-6=0

To find:

The quadratic formula for the given equation after substituting the values.

Solution:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

We have,

16x^2-20x-6=0

In this equation, a=16,b=-20,c=-6.

Substituting a=16,b=-20,c=-6 in the above formula, we get

x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}

Therefore, the required quadratic formula for the given equation after substituting the values is x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}.

3 0
3 years ago
Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of t
scZoUnD [109]
2L + 2W = 62
2(20) + 2W=62
40+ 2W=62
62-40=22
2W=22
22 divided by 2 is 11

W= 11
8 0
3 years ago
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