Answer:
A positive slope results when an individual is moving away from the origin.
Explanation:
really i dont know i just picked C and got it right
The answer is A. The first cell is in the anaphase I and the second cell is
in the anaphase II.
Meiosis is a cell division which results in the
reduction of chromosome number by half - from diploid to haploid - in
daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces two
haploid cells. Meiosis II is analogous to mitosis, so in total,
meiosis results in four haploid cells. So, in meiosis there are two anaphases -
the anaphase I in meiosis I and the anaphase II in meisosis II.
<span>
</span>
<span>In anaphase I, the sister chromatids separate
from each other to the opposite sides of the cells. In meiosis I there are 46
chromosomes in duplicate, which are present as pairs of sister
chromatids. In anaphase of meiosis II, since the cell is
haploid, there are 23 chromosomes in duplicate, which are
present as sister chromatids.</span>
The answer you may be looking for perhaps is Histone.
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
