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2 years ago

What is x and what is y in 4x-2y=4

Mathematics

1 answer:

Fed [463]2 years ago

5 0

Answer:

x = 1/2y + 1

y = 2x - 2

Step-by-step explanation:

Let's solve for x.

4x−2y=4

Step 1: Add 2y to both sides.

4x−2y+2y=4+2y

4x=2y+4

Step 2: Divide both sides by 4.

2y+4

y+1

Answer:

y+1

Let's solve for y.

4x−2y=4

Step 1: Add -4x to both sides.

4x−2y+−4x=4+−4x

−2y=−4x+4

Step 2: Divide both sides by -2.

−2y

−2

−4x+4

−2

y=2x−2

Answer:

y=2x−2

Hope this helps!

brainliest?

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2 years ago

6 pounds of apples and 3 pounds of oranges cost 24 dollars.5 pounds of apples and 4 pounds of oranges cost 23 dollars. Set up a

vitfil [10]

Answer:cost of each pound of apple= $3

And cost of each pound of orange =$2

Step-by-step explanation:

Step 1

Let cost of apples = x

And cost of Oranges =y

Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as

6 x + 3y= 24----- equation 1

Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as

5x+ 4y= 23----- equation 2

Step 2

6 x + 3y= 24----- equation 1

5x+ 4y= 23----- equation 2

Using substitution method to solve the equation

6 x + 3y= 24

24-6x=3y

y= 24-6x/3 = 8-2x

Y= 8-2x

Substituting the value of y= 8-2x into equation 2

5x+ 4( 8-2x)= 23

5x+ 32 -8x= 23

32-23= 8x-5x

9=3x

x=9/3

x=3

Putting the value of x= 3 in equation 1 and solving to find y

6 x + 3y= 24

6(3) +3y= 24

18+3y=24

3y= 24-18

3y=6

y=6/3= 2

Therefore the cost of each pound of apple= $3

And cost of each pound of orange =$2

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Mumz [18]

$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
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\\
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