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Ivahew [28]
3 years ago
12

Evaluate 4 + (-2) - (-3) – 6.

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

4 t -2= 6 -3=3-6=3  6 x 3= 18 x 3=54

Step-by-step explanation:

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This year 426,731 people visited a water park.last year 102,865 fewer people visited the park the year the park opened 84,007 fe
mylen [45]

Answer:

236,859 people visited the water park the year it opened.

Step-by-step explanation:

426,731 - 102,865= 323,866 the amount of people that visited last year

323,866 - 87,007 = 236,859 the amount of people that visited the water park the year it opened

7 0
3 years ago
1-cot^2a+cot^4a=sin^2a(1+cot^6a) prove it.​
aliina [53]

Step-by-step explanation:

We have

1-cot²a + cot⁴a = sin²a(1+cot⁶a)

First, we can take a look at the right side. It expands to sin²a + cot⁶(a)sin²(a) = sin²a + cos⁶a/sin⁴a (this is the expanded right side) as cot(a) = cos(a)/sin(a), so cos⁶a = cos⁶a/sin⁶a. Therefore, it might be helpful to put everything in terms of sine and cosine to solve this.

We know 1 = sin²a+cos²a and cot(a) = cos(a)/sin(a), so we have

1-cot²a + cot⁴a = sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

Next, we know that in the expanded right side, we have sin²a + something. We can use that to isolate the sin²a. The rest of the expanded right side has a denominator of sin⁴a, so we can make everything else have that denominator.

sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

= sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

We can then factor cos²a out of the numerator

sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

= sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

Then, in the expanded right side, we can notice that the fraction has a numerator with only cos in it. We can therefore write sin⁴a in terms of cos (we don't want to write the sin²a term in terms of cos because it can easily add with cos²a to become 1, so we can hold that off for later) , so

sin²a = (1-cos²a)

sin⁴a = (1-cos²a)² = cos⁴a - 2cos²a + 1

sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-2cos²a+1-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

factor our the -cos²a-sin²a as -1(cos²a+sin²a) = -1(1) = -1

sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

=  sin²a + cos²a (cos⁴a-1 + 1)/sin⁴a

= sin²a + cos⁶a/sin⁴a

= sin²a(1+cos⁶a/sin⁶a)

= sin²a(1+cot⁶a)

8 0
2 years ago
If R=1/2(a+b)k, fins in terms R,a and b​
Fittoniya [83]

Answer:

{ \tt{R =  \frac{1}{2}(a + b)k }} \\ { \tt{2R = (a + b)k}} \\ { \tt{k =  \frac{2R}{a + b} }}

7 0
3 years ago
Finding the Range
rusak2 [61]

Answer:

89

Step-by-step explanation:

92 - 3 =89

subtract smallest from largest

6 0
2 years ago
Scientific notation without common powers of ten
morpeh [17]

Answer:

1.16*10⁻¹ or 1.16E-1

Step-by-step explanation:

(5.8*10⁻⁶)(2*10⁴)

5.8*2*10⁻⁶*10⁴

11.6*10⁻²

1.16*10⁻¹

1.16E-1

5 0
3 years ago
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