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AlekseyPX
2 years ago
12

I will 10 points pls anwser correct

Mathematics
1 answer:
coldgirl [10]2 years ago
4 0

Answer:

1.5 if you Evaluate and in fraction form \frac{15}{10}

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An electronics company packages its product in cube-shaped boxes. These boxes are placed into a larger box that measures 3 ft lo
gladu [14]

The number of boxes fitted in the larger container is found out by the volume of both boxes.

The number of boxes fitted into the larger container is 480.

<h3>What is the volume?</h3>

The volume can be defined as the space occupied by an object in three dimensions.

Given that the edge of the cube box is 1/4 ft. The dimensions of the larger box are 3 ft long, 1 1/4 ft wide, and 2 ft.

The volume of the cube box is calculated as given below.

V_s = s^3

Where Vs is the volume of the cube box and s is the edge of the cube box.

V_s = \dfrac {1}{4}^3

V_s = 0.015625\;\rm ft^3

The volume of the larger box is calculated as given below.

<em />V = l \times w\times h

Where V is the volume, l is length, w is width and h is the height of the larger box.

V = 3 \times \dfrac {5}{4} \times 2

V = 7.5\;\rm ft^3

The number of cube boxes fitted into the larger box is calculated as given below.

No. \; of \;boxes = \dfrac {V}{V_s}

No. \; of \;boxes = \dfrac {7.5}{0.015625}

No. \; of \;boxes = 480

Hence we can conclude the number of boxes fitted into the larger container is 480.

To know more about the volume, follow the link given below.

brainly.com/question/1578538.

8 0
2 years ago
Solve this problem<br> √-16
a_sh-v [17]

Answer:

4i

Step-by-step explanation:

\sqrt{-1}  = i

Therefore \sqrt{-16} = \sqrt{16} \sqrt{-1} \\=4i

3 0
3 years ago
The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th
Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

A=\frac{1}{2} (b_{1} +b_{2} )h

where, h be the height of the trapezoid

b_{1} be the shorter base

b_{2} be the longer base

As per the given problem,

b_{2}=b_{1}  +6

Now,

Putting, A=72, b_{2}=b_{1}+6 and h=6 we get,

\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72

or, b_{1}+b_{1}+6 = \frac{(72)(2)}{6}

or, 2b_{1}+6 = 24

or, 2b_{1}=24-6

or, b_{1}= \frac{18}{2}

or, b_{1}=9

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0
3 years ago
I need help with the last one
RoseWind [281]
The last one you’re correct , 16 is a perfect example of a perfect square
5 0
3 years ago
Which translation will change figure ABCD to figure A'B'C'D'
Elan Coil [88]

Answer:

go up 8, go left -4

6 0
3 years ago
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