Answer:
the answer is 13 1/3 pi.
Step-by-step explanation:
first, you solve the area of the smaller circle, 3^2 times pi, 9pi. since 120 is 1/3 360, it means it is 1/3 of the cirlce. 9/3=3. 3 is what you have to subtract. next, you know the radius of the big circle is 7 and 7^2 times pi is 49 pi. again, you know 120 is 1/3 360 so it has to be 49/3 pi. 49/3pi - 3pi= 13 1/3 pi.
Solve for b by simplifying both sides of the equation, then isolating the variable.
b = -8/5 + a/5
<span>Divide -3x^3-2x^2-x-2 by x-2</span>
Answer:
Option(b) is the correct answer to the given question
Step-by-step explanation:
1) If then , there must be a positive Autocorrelation
According to it if the ratio d of durbin-watson is equal to or less than dL then it is called as Positive Autocorrelation.
2 ) if , then it is Inconclusive
According to it If the coefficient d of the Durbin-Watson is between dL & du then it is called as Inconclusive.
3) if then there is No proof of the Autocorrelation
According to it if the d of the durbin-watson will be less than or equivalent to du then it is called as No Autocorrelation.
4) If ) then there is No proof of the Autocorrelation
According to it if the d of the durbin-watson will be less than or equivalent to 4- du then it is called as No Autocorrelation.
5) If the , then it is Inconclusive
According to it if the d of the durbin-watson is between the then it is called as Inconclusive.
6) If the then it called as negative Autocorrelation
According to it if the d of the durbin-watson is greater then then it is called as negative autocorrelation.
- From the point 6 we can say that the option(B) is correct
- All the others options are not correct for (4 − dL), so these are incorrect option .