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Wittaler [7]
3 years ago
12

Will the point of the arrow in Figure Bhave the same angle measure as the point of the arrow in Figure A? Explain your answer.

Mathematics
2 answers:
neonofarm [45]3 years ago
8 0

Answer: its confuseind

Step-by-step explanation: 25w5 265

Nina [5.8K]3 years ago
7 0

Answer: I'm not sure

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In ΔABC, where ∠C is a right angle, cos A=√21/5. What is sin B?
Stolb23 [73]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
1-Suppose the path of a baseball follows the path graphed by the quadratic function ƒ(d) = –0.6d2 + 5.4d + 0.8 where d is the ho
jasenka [17]

Answer:

1. The correct option B.

2.The correct option A.

Step-by-step explanation:

The given function is

f(d)=-0.6d^2+5.4d+0.8

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

0=-0.6d^2+5.4d+0.8

Quadratic formula:

d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using the quadratic formula we get

d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}

d=-0.146,9.146

Therefore the ball is in air between d=-0.146 to d=9.146.

The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

9.146\approx 9.15

Therefore the correct option is B.

2.

The given equation is

y=(x-1)^2+1                 .... (1)

The standard form of parabola is

y=a(x-h)^2+h             .... (2)

Where, a is constant and (h,k) is vertex.

On comparing (1) and (2), we get

a=1

h=1

k=1

Since the value of a is positive, therefore it is an upward parabola. The vertex of the parabola is (1,1).

Put x=0 in the given equation.

y=(0-1)^2+1

y=1+1=2

Therefore the y-intercept is (0,2) and option A is correct.

8 0
3 years ago
Which of the following is an arithmetic sequence with common difference 2?
Dvinal [7]
D.

cause it’s adding two to get to the next one
3 0
3 years ago
Lesson 10 adding and subtracting in scientific notation
Gnoma [55]
What about lesson 9?
3 0
4 years ago
The equation of a parabola with a vertex at the origin is y= 1/4px^2 if 4p=-16, what are the coordinates of the focus ?
lilavasa [31]

Answer:

Co-ordinates of the focus is; (0, -4)

Step-by-step explanation:

We are given;

Vertex at origin; (0, 0)

Equation of parabola; y = x²/4p

4p = -16

Now,in parabola with vertex at origin, the coordinates of the focus is usually at (0, p)

Now, from 4p = -16 we can find p

p = -16/4

p = -4

Thus coordinates of the focus is; (0, -4)

4 0
3 years ago
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