Answer:
She used 67/60 of a bag of gravel in one day.
Step-by-step explanation:
We must get a common denominator so we can add the two fractions.
Let's use 60!
1/5 = 12/60
11/12 = 55/60
Now we can add and get 67/60!
She used 67/60 of a bag of gravel in one day.
Hi!
The answer is one
When you solve this system of equations you get an answer for y and an answer for x.
It looks kinda like this: x=3, y=-4
Thus, your answer is one solution
I hope this helps!
Feel free to give brainliest if you think I deserve it!
EDITED: Answer: Phillip can order 12 different ways of ice cream.
Step-by-step explanation:
Ahem.
He can only have Vanilla or Chocolate. So let's pet them in a separate Row.
<u>Vanilla </u>
- With Sprinkles
- With Almonds
- With Hot Fudge
- With Sprinkles and Almonds
- With Sprinkles and Hot Fudge
- With Almonds and Hot Fudge
<u>Chocolate</u>
1.With Sprinkles
2.With Almonds
3.With Hot Fudge
4.With Sprinkles and Almonds
5.With Sprinkles and Hot Fudge
6.With Almonds and Hot Fudge
Answer:
Dina's friend is jealous of Dina's confidence so she wanted to "what up" her :)
Step-by-step explanation:
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
