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2 years ago

I need to know what the answer is plz help

Mathematics

2 answers:

balu736 [363]2 years ago

3 0

What’s the question ?

kykrilka [37]2 years ago

3 0

Could you say the question i cant answer it?

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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the

earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0

3 years ago

Lieutenant James made an average of 3 arrests per week for 4 weeks. How many arrests does she need to make in the fifth week to

tankabanditka [31]

Answer:

Step-by-step explanation:

We want the average arrests to be 4. It can be done by calculating the average between the average arrests and arrests during the 5th week, so we get:

Avg(1,2,3,4,5) = (Avg(1,2,3,4) + A(5)) / 2

Where Avg(x) is the average of arrests in given weeks, and A(x) is the number of arrests in a given week.

Solving for A(5) => A(5) = 2*Avg(1,2,3,4,5) - Avg(1,2,3,4) = 2 * 4 - 3 = 8-3 = 5

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3 years ago

Find the GCF of 20 and 30. 02 05 O 10 O 15

vitfil [10]

Answer:

Step-by-step explanation:

10 is the greatest common factor of 20 and 30

4 0

3 years ago

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Which relationship is always true for the angles are rxyz of triangle ABC

HACTEHA [7]

Answer:

congruency

Step-by-step explanation:

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3 years ago

Gregory spins the spinner once. What is P(vowel)? PLEASE HELP ME!!!

NikAS [45]

Answer:

There is two vowels and 6 sections in total

2 wanted sections / 6 total sections = 1/3

1/3 chance or 33.33333%

Step-by-step explanation:

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3 years ago