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koban [17]
3 years ago
10

Please can someone help been struggle with this problem

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

Step-by-step explanation:

domain = { x/ x € Real}

range = { y/ y > -3 , y € Real }

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Expand (n+5)*2 by using the perfect square pattern
mario62 [17]
N^2 + 25 if you mean *2 is squared.
8 0
3 years ago
Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)
Monica [59]

Answer:

\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices \mathsf{A(x_A, y_A)}, \mathsf{B(x_B, y_B)} and \mathsf{C(x_C, y_C)}, have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  \mathsf{x_A} & \mathsf{y_A }& 1 \\  \mathsf{x_B} &  \mathsf{ y_B} & 1 \\ \mathsf{ x_C} &  \mathsf{ y_C} & 1 \end{array} \right|}{2}

So, applying this knowledge we're going to have,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  3 & -7 & 1 \\ 6 &  4 & 1 \\ -2 &  -3 & 1 \end{array} \right|}{2}

\mathsf{A} \triangle =  \dfrac{1}{2}\left[  \left.\begin{array}{ccc}   3 & -7 & 1 \\ 6 &  4 & 1 \\ -2&  -3 & 1 \end{array}  \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]

\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}

\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}

Hope you enjoy it, see ya!)

\green{\mathsf{FROM}}: Mozambique, Maputo – Matola City – T-3

DavidJunior17

3 0
3 years ago
Which of the following values is the solution to the equation
Alchen [17]

Answer:

1.) 3

Step-by-step explanation:

<u>Divide each side by -35. Whatever you do to one side of the equation, you must do to the other side.</u>

<u />

<u />\frac{-35x}{-35} = \frac{-105}{-35}

X = 3

6 0
3 years ago
A stack of round crackers are in the shape of an oblique cylinder. The diameter of each cracker is 6 centimeters and the height
tekilochka [14]

Answer: 294cm

Step-by-step explanation:

The volume of a oblique cylinder is given by:

Volume= πr^2h

where

π = 3.14

r = radius

h = height

Radius= diameter/2 = 6/2 = 3

We have all the values, so we put it in the formulae so we can get the answer.

Volume= πr^2h

= 3.14 × 3 × 3 × (0.4 × 26)

= 294cm

8 0
3 years ago
If b is the midpoint of ac, ab=12x+11 and bc= 14x - 1, find AB
xxMikexx [17]

Answer:

AB = 83

Step-by-step explanation:

The mid-point of any segment divides the segment into two equal parts

∵ B is the midpoint of segment AC

→ That means B divides AC into two equal segments AB and BC

∴ AB = BC

∵ AB = 12x + 11

∵ BC = 14x - 1

→ Equate them

∴ 14x - 1 = 12x + 11

→ Subtract 12x from both sides

∵ 14x - 12x - 1 = 12x - 12x + 11

∴ 2x - 1 = 11

→ Add 1 to both sides

∵ 2x - 1 + 1 = 11 + 1

∴ 2x = 12

→ Divide both sides by 2

∵ \frac{2x}{2}=\frac{12}{2}

∴ x = 6

→ To find AB substitute x by 6 in its expression

∵ ab = 12x + 11

∵ x = 6

∴ AB = 12(6) + 11

∴ AB = 72 + 11

∴ AB = 83

3 0
3 years ago
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