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kirza4 [7]
3 years ago
8

PLS PLS PLS PLS HELP!!

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

125 ang answer

thats my final

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Answer:

i need help with this also it  is confusing is yours a test???

Step-by-step explanation:

6 0
3 years ago
The equation tan(x- pi/3) is equal to _____.
kherson [118]

Answer:

B

Step-by-step explanation:

Using the expansion

tan(x - y) = \frac{tanx-tany}{1+tanxtany}, then

tan(x - \frac{\pi }{3})

=  \frac{tanx-tan(-\frac{\pi }{3}) }{1+tanxtan(-\frac{\pi }{3}) }

note that tan( -\frac{\pi }{3}) = - tan(\frac{\pi }{3}) = - \sqrt{3}

= \frac{tanx-(-\sqrt{3}) }{1+tanx(-\sqrt{3}) }

= \frac{tanx+\sqrt{3} }{1-\sqrt{3}tanx } → B

6 0
3 years ago
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$1500 is invested at a rate of 3% compounded monthly. Write a compound interest function to model this situation. Then find the
Marianna [84]

Answer:

<u>Equation</u>:  F=1500(1.0025)^{12t}

<u>The balance after 5 years is:  $1742.43</u>

<u></u>

Step-by-step explanation:

This is a compound growth problem . THe formula is:

F=P(1+\frac{r}{n})^{nt}

Where

F is future amount

P is present amount

r is rate of interest, annually

n is the number of compounding per year

t is the time in years

Given:

P = 1500

r = 0.03

n = 12 (compounded monthly means 12 times a year)

The compound interest formula modelled by the variables is:

F=1500(1+\frac{0.03}{12})^{12t}\\F=1500(1.0025)^{12t}

Now, we want balance after 5 years, so t = 5, substituting, we get:

F=1500(1.0025)^{12t}\\F=1500(1.0025)^{12*5}\\F=1500(1.0025)^{60}\\F=1742.43

<u>The balance after 5 years is:  $1742.43</u>

3 0
3 years ago
When can a trapezoid also be called a parallelogram?
saveliy_v [14]

Answer:

Yes, because it has one pair of parallel sides.

Step-by-step explanation:

4 0
3 years ago
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Find the length of one side of a rhombus with diagonals 30 and 72
fgiga [73]

Answer:

51

Step-by-step explanation: I hope I'm not wrong :)

8 0
3 years ago
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