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aliina [53]
3 years ago
11

The length of a rectangle is four times its width.

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

{\huge{\underline{\sf{Answer:}}}}

<h3>» The length of the rectangle is <u>40 cm</u>, while the width is <u>10 cm</u>.</h3>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>

Let us understand a few concepts:

  • the length <em>l</em><em> </em>of the rectangle is four times its width <em>w</em>, so we let the length <em>l</em><em> </em><em>=</em><em> </em><em>4</em><em>w</em>.
  • the perimeter of the rectangle is 100 cm.

Given that the perimeter of the rectangle is given by the formula P = 2 (l + w), we can solve for the missing values by forming an equation:

  • P = 2 (l + w)
  • 100 = 2 (l + w)
  • 100 = 2 (4w + w)
  • 100 = 2 (5w)
  • 10w = 100
  • w = 100/10
  • <u>w = 10</u><u> </u><u>c</u><u>m</u>

Now we know the value of the width, which is 10 cm, we now solve for the length such that the length is four times the width.

  • l = 4w
  • l = 4(10)
  • <u>l = 40 cm</u>

{\: \:}

{\huge{\underline{\sf{Hope\:It\:Helps}}}}

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