Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Here's the equation:
5 + x=39
-5 -5
Here's the answer: x=34
I think 8.0 is the answer
Answer:
x=15º
Step-by-step explanation:
180=25+8x+5+2x
180=30+10x
180-30=10x
150=10x
15=x
The answer in simplest form would be 2 and 3 fifths gallons of gas.