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Anton [14]
3 years ago
14

-

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

Step-by-step explanation: Given a number N. Given two numbers X and Y, the task is to find the sum of all those numbers from 1 to N that are divisible by X or by ... Sn = (n/2) * {2*a + (n-1)* d} ... + (N / (X * Y) - 1) * (X * Y))/ 2;. return S1 + S2 - S3;. } // Driver code. int main().

hope this is right

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1) Find the general solution to the following differential equation x^3•y’- y = 0
maxonik [38]

Answer:

y(x) = c_1 e^(-1/(2 x^2))

Step-by-step explanation:

Solve the separable equation x^3 (dy(x))/(dx) - y(x) = 0:

Solve for (dy(x))/(dx):

(dy(x))/(dx) = y(x)/x^3

Divide both sides by y(x):

((dy(x))/(dx))/y(x) = 1/x^3

Integrate both sides with respect to x:

integral((dy(x))/(dx))/y(x) dx = integral1/x^3 dx

Evaluate the integrals:

log(y(x)) = -1/(2 x^2) + c_1, where c_1 is an arbitrary constant.

Solve for y(x):

y(x) = e^(-1/(2 x^2) + c_1)

Simplify the arbitrary constants:

Answer:  y(x) = c_1 e^(-1/(2 x^2))

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2 years ago
9. Which one of the following dealt with
Elden [556K]

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lskwmzkmsmqmqmqkzkzzlosmz

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3 years ago
will deposited $1550 in an account that pays 8% annually. How much would be in the account at the end of 24 months? ​
nikdorinn [45]

Answer:

$1798

Step-by-step explanation:

You take the money of 1550 and multiply the 16% for the 2 years, which is just 1.16 and you get 1798

7 0
2 years ago
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Write the equation of the line that passes through the given points (0,-4) and (-7,-10
Anettt [7]

Answer:

14/-7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Tính tích phân sau bằng cách dùng tọa độ cực I=∫∫ <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%5E%7B2%7D%20%2B
xenn [34]

It sounds like <em>R</em> is the region (in polar coordinates)

<em>R</em> = {(<em>r</em>, <em>θ</em>) : 2 ≤ <em>r</em> ≤ 3 and 0 ≤ <em>θ</em> ≤ <em>π</em>/2}

Then the integral is

\displaystyle \iint_R\frac{\mathrm dx\,\mathrm dy}{\sqrt{x^2+y^2}} = \int_0^{\pi/2}\int_2^3 \frac{r\,\mathrm dr\,\mathrm d\theta}{\sqrt{r^2}} \\\\ = \int_0^{\pi/2}\int_2^3 \mathrm dr\,\mathrm d\theta \\\\ = \frac\pi2\int_2^3 \mathrm dr \\\\ = \frac\pi2r\bigg|_2^3 = \frac\pi2 (3-2) = \boxed{\frac\pi2}

5 0
3 years ago
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