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Anton [14]
3 years ago
14

-

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

Step-by-step explanation: Given a number N. Given two numbers X and Y, the task is to find the sum of all those numbers from 1 to N that are divisible by X or by ... Sn = (n/2) * {2*a + (n-1)* d} ... + (N / (X * Y) - 1) * (X * Y))/ 2;. return S1 + S2 - S3;. } // Driver code. int main().

hope this is right

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