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3 years ago

6

−2/3 + 2 3/8 Please help me :)

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

41/21 fraction decimal 1.71

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PLEASE HELP ONE QUESTION THATS IT

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-3,2 -2,4 1,-1

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3 years ago

Round 1.764 to the nearest tenth

Ann [662]

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1.8................................

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What is the equivalent of 1/50 : fraction , in decimal form

lina2011 [118]

What is the equivalent of 1/50: fraction , in decimal form? We can determine the equivalent values of the fraction 1/50 in one simple way.
By dividing 1 and 50 to get the quotient of the digits given. <span><span>

1. </span>1 / 50 = 0.02</span>

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3 years ago

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snow_tiger [21]

Answer:

13.63 miles per hour

Step-by-step explanation:

100 yards / 15 sec converted to miles per hour

<u>100 yards</u> x <u> 60 sec</u> x <u> 60 min</u> x <u> 1 mile </u> = 13.63 miles/hr

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the mistake on Mrs Dukes is the conversion from miles to yards.

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7 0

3 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

a

$P(\= X \ge 51 ) =0.0062$

b

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

So

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

2 years ago