Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
The constant of <u>p</u><u>r</u><u>o</u><u>p</u><u>o</u><u>r</u><u>t</u><u>i</u><u>o</u><u>n</u> is the value that relates two variables that are directly proportional or inversely proportional.
- <em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>B</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em>!</em><em>!</em><em>~</em>
Answer:
it is to help me out but the answer is 59-=9x67-=7
Step-by-step explanation:
the answer is 7
Assigning "a" as cost of adult tickets and "c" the cost of children's tickets.
3a + 4c = 107
2a + 3c = 76
elimination method
2(3a + 4c = 107)
-3(2a + 3c = 76)
6a + 8c = 214
-6a - 9c = -228
----------------------
0 - c = - 14
c = 14
Then 2a + 3(14) = 76
2a = 76 - 42
2a = 34
a = 34/2
a = 17
