Question

What is the equation of the line that is perpendicular to Y= -2/3X+4 and that passes through (-2,-2)?

Answer 1

Answer:

y=3/2x+1

Step-by-step explanation:

You’re trying to find the perpendicular like equation of y=-2/3x+4 that passes through (-2,-2). Use reciprocal of slope -2/3= 3/2. use y=mx+b and plug in info, (-2,-2) will be plugged in for both y and x and 3/2 will be plugged in for m making -2=(3/2)(-2)+b. Multiply the () to get -2=-3+b, add 3 to both sides of the equation to get 1=b. Use your info to make the finished equation y=3/2x+1

Answer 2

Answer:

$y = \frac{3}{2}x + 1$

Step-by-step explanation:

-2 = 1½[-2] + b

-3

1 = b

y = 1½x + 1

** 1½ = 3⁄2

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES]:

-⅔ → 1½

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