Question

In an election, there were only two candidates for the post of president. The winning candidate got 53% of the total votes. His opponent got 31000 votes which represented 31% of the total votes. Find (a) the number of votes and (b) the winning margin.
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Answer 1

Answer:

(a)100,000

(b)53,000

Step-by-step explanation:

(a)

Let the total votes be x.

Given 31% of x=31000

$31 \times \frac{x}{100}$

$= 31000$

$x= 100 000$

So,total votes are =100,000

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(b)

$Winning \: candidate \: got = \frac{53 \times 100000}{100}$

$=53,000$

Winning margin =53000−31000=22000.

=$22000$

Therefore, the Winning margin is 22000.

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Answer 2

Question:

In an election, there were only two candidates for the post of president. The winning candidate got 53% of the total votes. His opponent got 31000 votes which represented 31% of the total votes. Find (a) the number of votes and (b) the winning margin.

Answer:

22000

step by step explanation:

Let the total votes be x.

Given 31% of x = 31000

$= > 31 \times \frac{x}{100}$

$= > 31000$

$x = 100000$

So, Total votes are = 100000

Winning candidate got

$= > 53\% \: of \: 100000$

$= > \frac{53}{100} \times 100000$

(you can cancel the zeros near hundred and also 2 zeros near lakh)

$= > \frac{53}{1} \times 1000$

$= > 53000$

Winning margin

= 53000 - 31000

= 22000

•°• The winning margin is 22000