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patriot [66]
2 years ago
15

What is the solution m<1?

Mathematics
1 answer:
olchik [2.2K]2 years ago
5 0

Answer:         D

Step-by-step explanation: becaus elook at it bitlkjmnjhnnjh

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Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the
Marta_Voda [28]

Answer:

Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the <u><em>shortest side</em></u>.

8 0
3 years ago
Read 2 more answers
Someone PLEASE help me!!!!!<br> Evaluate -/3/
Veseljchak [2.6K]

if / means absolute value, then the answer is -3. The absolute value of 3 is 3, then you take the negative value of it, which is -3.


Btw, the absolute sign is ||, not //.


5 0
3 years ago
AYUDA POR FAVOR, ES URGENTE ​
Alika [10]

Answer:

212

Step-by-step explanation:

13 * 17 = 221

221- 9 = 212

6 0
3 years ago
so we have a small issue. I dont know how to figure this out and I dont know what equivalent means :/ so if you can help me that
Mars2501 [29]

Equivalent means "equal to"

Because we are looking for an equation that is not equivalent to 3y + x = 18, we need to find one that is not equal to 3y + x = 18.

First, lets try y = 6 - 1/3x

3y + x = 18

Divide the whole of both sides by 3

y + 1/3x = 6

Then, subtract 1/3x from each side

y = 6 - 1/3x

So, y = 6 - 1/3x IS equivalent to 3y + x = 18, so it is not the answer.

Next, lets try y - 5 = -1/3 (x - 3)

First, we need to distribute the -1/3 in the right side.

y - 5 = -1/3x + 1

Add 5 to each side

y = -1/3x + 6

Add 1/3x to each side

y + 1/3x = 6

So, y + 1/3x = 6 is NOT equivalent to 3y + x = 18, so it IS an answer.

Lets try the third one: y - 5 = 1/3(x + 3)

We need to use distributive property again on the right side

y - 5 = 1/3x + 1

Add 5 to each side

y = 1/3x + 6 is not equivalent to 3y + x = 18 so it IS and answer

Lets test the last one: 6y + 2x = 36

Divide the whole of each side by 2

3y + x = 18 IS equivalent to 3y + x = 18 so it is NOT an answer

4 0
3 years ago
Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum
lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\

\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\  (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\

=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3}  \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\

4 0
2 years ago
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