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3 years ago

Quiz 5:1 midsegments

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

Step-by-step explanation:

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Answer:

6 nights with 4 logs left over

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2 years ago

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Write the equation of the line with a slope of 24 and a y-intercept of -5

zmey [24]

Answer:

$y=24x-5$

Step-by-step explanation:

General slope intercept form equation of straight line is given as

$y=mx+b$

where m is slope and b is y-intercept

here m=24 and b=-5

Therefore

$y=mx+b=24x-5$

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3 years ago

PLSSS HELP PLS I WILL GIVE BRAINLIEST TO CORRECT PERSON!! 13 POINTS. Camille dilates a digital photograph by a factor of 1.25 to

siniylev [52]

Answer:

the first one is A, the second one is D.

Step-by-step explanation:

For the perimeter you have to multiply by the original dilation number, and for the area, you have to dilate by 2.5

Hope this helps :D

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3 years ago

Arturo purchased a package of 50 blank CDs. After he used “x” CDs, he had “x” less than 50 CDs remaining. How many CDs did he ha

Katarina [22]

Answer:

19 Cds left.

Step-by-step explanation:

The question said he used 31 Cds, so 50 minus 31 is 19.

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3 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

3 years ago