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PtichkaEL [24]
3 years ago
15

2 candy bars cost $0.98. At this rate, how much do 5 candy bars cost? The total cost for five candy bars is?

Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

$2.45

Step-by-step explanation:

First divide the cost by number of items. you shall get $0.49

Now multiply the cost of 1 candy bar into 5 and you shall get $2.45.

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A health club sold ten memberships in one week for total of $3000. If male memberships cost $300 and female memberships cost $30
Ket [755]

Answer:

Step-by-step explanation:

The reason you haven't gotten an answer to this is because in its current formatting, there is no answer. Here's what I mean:

The first equation is going to be concerning the NUMBER of memberships sold, where m is male and f is female. The total number of memberships was 10:

m + f = 10

Now for the money equation. The total amount of money made from that number of memberships was 3000, where male memberships cost $300 and so do the female memberships, giving us an equation of

300m + 300f = 3000

Go back to the first equation and solve for either m or f. I solved for m in terms of f:

m = 10 - f and sub that into the second equation for m to get:

300(10 - f) + 300f = 3000 and

3000 - 300f + 300f = 3000. Here is where you find the problem. The -300f and the 300f cancel each other out, leaving you with the fact that

3000 = 3000 which it does, but it doesn't give us any viable answer.

I would have to say that since we can't do math on this, that the most credible answer you'll find is that the same number of male and female memberships were sold because 5 male memberships cost $1500 (5 memberships at $300 a piece is $1500) and 5 female memberships also cost $1500.

1500 + 1500 = 3000

6 0
3 years ago
Simplify <br> −5x^4(−3x^2+4x−2)
malfutka [58]
112 me dió a eso mira haber si es si no trate.
6 0
3 years ago
the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant
Tamiku [17]

Answer:

The rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters is 24\pi \:\frac{cm^3}{s}

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

  • \frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • \frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}
  • The volume of a cone of radius r and height h is given by V=\frac{1}{3} \pi r^2 h

We want to find the rate of change of the volume \frac{dV}{dt} when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]

Substituting the values we know into the above formula:

\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}

5 0
4 years ago
Please help me answer this :) <br> Explain your answer <br><br> Will give brainiest
lora16 [44]

Answer:

A: Store A will cost about $1.28 less

Step-by-step explanation:

Okay, let's find the unit rate of cost. To find that for store A, we divide 7.26 by 3, which gets us 2.42. For store B, we need to look for the first intersection. We find that at (20, 50). Let's divide 50 by 20. That gets us 2.50. Let's multiply 2.42 and 2.50 by 16. That gets us 38.72 for store A and 40 for store B. Let's subtract 38.72 from 40. That gets us 1.28. That means store A costs $1.28 less than store B. That makes our answer A.

4 0
3 years ago
Read 2 more answers
Need help with #2 and #3 all of the problem
-Dominant- [34]

Answer:

ang hirap wag nlang hahahahahahahaha

3 0
3 years ago
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