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joja [24]
3 years ago
5

Someone please help me I’m stuck on this problem

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0
I think it’s either 8 or negative 8
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consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations
emmasim [6.3K]

Answer:

x=1 and x=4

Step-by-step explanation:

We have the following system of equations:

y=\sqrt{x} and y=x-2

To solve the problem, we need to equal the two equations:

x-2=\sqrt{x} ⇒ (x-2)^{2} =x ⇒ x^{2} -4x + 4 = x  

⇒ x^{2} -5x + 4 = 0  

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are x=-1 and x=-4.

Then, the factorized form of the polynomial is: (x-1)(x-4).

The, the solution to the system of equations is: x=1 and x=4.

5 0
3 years ago
Sean got m marks for his math test.Emma got 15 more marks than Sean Emma score is 97
Dafna1 [17]
97-15=82 so he got 82
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What is the greatest common factor of the polynomial -25y^3+15y^2-5y
Sonbull [250]

Answer:

-5y

Step-by-step explanation:

4 0
3 years ago
!!!WILL MARK BRAINLIEST!!
Leya [2.2K]

Answer:

the answer is D

Step-by-step explanation:

6 0
3 years ago
Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio
Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that p = 0.8

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is P(X \geq 1) when n = 2. So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96

0.96 = 96% probability that at least one of them detect an enemy attack.

6 0
3 years ago
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