The sample is 200 randomly selected students.
The following things should be considered:
- Let us assume the no of siblings for each student be x.
- Now for determining the mean no of siblings she choose 200 students.
So, here the sample should be 200 randomly selected students.
Therefore the other options should be incorrect.
Thus we can conclude that the sample is 200 randomly selected students.
Learn more about the sample here: brainly.com/question/13287171
We let y equal to the elevation above sea level so that the elevation of the rock climber after x minutes of climbing would be:
y = 2x + 50
His initial height can be calculated when x is equal to zero it is when the climber is not yet climbing. Therefore, the rock climber'sinitial height above sea level would be 50 meters.
14/84 x100 =. 1/6 x 100 = 16.66%
<span>-2x-3=y in standard form
=
2x + y = -3
hope it helps</span>
Answer:
n = 66.564
Step-by-step explanation:
- Because the population is unknown, we will apply the following formula to find the sample size:

Where:
z = confidence level score.
S = standard deviation.
E = error range.
2. We will find each of these three data and replace them in the formula.
"z" theoretically is a value that measures how many standard deviations an element has to the mean. For each confidence level there is an associated z value. In the question, this level is 99%, which is equivalent to a z value of 2.58. To find this figure it is not necessary to follow any mathematical procedure, it is enough to make use of a z-score table, which shows the values for any confidence interval.
The standard deviation is already provided by the question, it is S = 100.
Finally, "E" is the acceptable limit of sampling error. In the example, we can find this data. Let us note that in the end it says that the director wishes to estimate the mean number of admissions to within 1 admission, this means that she is willing to tolerate a miscalculation of just 1 admission.
Once this data is identified, we replace in the formula:

3. The corresponding mathematical operations are developed:


n= 66.564