Question

3x^2 + 2x-4 = 0 help

Answer 1

Answer:

I dont know

Step-by-step explanation:

how to answer that

Answer 2

Answer:

${ \rm{3 {x}^{2} + 2x - 4 = 0 }}$

• let's use the quadratic formular to solve the quadratic equation given.

• Considering general quadratic equation; ax² + bx + c = 0

• therefore;

${ \tt{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }}$

• a is 3
• b is 2
• c is -4

• substitute following the mathematical operation rules:

${ \rm{x = \frac{ - 2 \pm \sqrt{ {2}^{2} - (4 \times 3 \times - 4) } }{(2 \times 3)} }} \\ \\ { \rm{x = \frac{ - 2 \pm52}{6} }}$

• split the values:

${ \rm{either \: \{x = \frac{ - 2 + \sqrt{52} }{6} \} \: \: or \: \: \{x = \frac{ - 2 - \sqrt{52} }{6} \} }} \\ \\ { \rm{either \: \{x = 0.87 \} \: \: or \: \: \{x = - 1.54 \}}}$