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Ganezh [65]
2 years ago
14

Can someone plsss help me with the circled question tysm if u doo :((

Mathematics
1 answer:
nika2105 [10]2 years ago
6 0

Answer:

4×sqrt(5) inches

Step-by-step explanation:

Pythagorean theorem states that (for right triangles) if you square each shorter side and add those together, you will get the sum of the longest side (hypotenuse) squared.

This is commonly written as:

a^2 + b^2 = c^2, where c is the hypotenuse.

((For right triangles this will always be opposite the 90° angle.))

Since you know one of the shorter sides and the hypotenuse, rewrite the equation as such:

c^2 - b^2 = a^2, where a is the unknown length

This goes to:

sqrt(c^2 - b^2) = a

sqrt((12in)^2 - (8in)^2) = a

sqrt(144sqin - 64sqin) = sqrt(80sqin) = a

This simplifies to:

sqrt(16sqin)×sqrt(5sqin) = 4in×sqrt(5sqin) = a

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What is another way to write the equation 3(1.25)+3(2.00)=9.75
Alexus [3.1K]

Answer:

3.75+6=9.75

Step-by-step explanation:

8 0
2 years ago
1/7=3/4x+1<br><br> Please help
zloy xaker [14]
Here, 1/7 = 3/4x + 1
3/4x = 1/7 - 1
3/4x = -6/7
x = -6/7 * 4/3
x = -2/7 * 4
x = -8/7

In short, Your Answer would be -8/7

Hope this helps!
3 0
3 years ago
Read 2 more answers
Solve the triangle for x.
nalin [4]

Answer:

90.4°

Step-by-step explanation:

Use Law of Cosines to solve:

12² = 9² + 8² - 2(9)(8)Cos X

  144 = 81 + 64 - 144Cos X

     -1 = -144Cos X

         -1/144 = Cos X

            Cos^-1 (-1/144) = X

                     X = 90.39789056°

8 0
3 years ago
Read 2 more answers
1/3x² + x+5/3x² = 1/9<br><br>HAHAHAHA......​
mr_godi [17]

Answer:

Now, 3x 2+x+5⩾0

This is because b² −4ac=1−4×5×3

=−59 (roots are imaginary)

3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0

2x²+7x−4=0

2x²+8x−x−4=0

2x(x+4)−1(x+4)=0

(2x−1)(x+4)=0

x= 1/2 and−4 but x≥3

∴ No solution.

lol hehehe

7 0
2 years ago
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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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