Answer:
axis of symmetry x=3/2
vertex (3/2, 0)
Step-by-step explanation:
to find the axis of symmetry we use h = -b/2a
where ax^2 + bx+c
h = -(-12)/2(4)
h= 12/8
h = 3/2
the axis of symmetry is x = 3/2
the x coordinate of the vertex is h x=3/2
to find k, the y coordinate of the vertex, substitute x=3/2 into the equation
y=4x^2-12x+9
y=4(3/2) ^2-12(3/2)+9
= 4 (9/4) - 6*3 +9
= 9-18+9
= 0
the vertex (3/2, 0)
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Answer:
(0,-4) (5,0)
Step-by-step explanation:
4x-5y=20
First, we must put the equation into slope intercept form: y= mx+b
5y=4x-20=y=4/5x-4
The y intercept, by definition, is b. In this scenario, b is -4.
One ordered pair that works is (0,-4).
Also, we can find the ordered pair for the x intercept. By definition, the x intercept is the value of x when y equals zero. hence, we substitute 0 for y and then we can find an ordered pair that works and solve for x!:
- 0=4/5(x)-4= 4=4/5x
- 4x=20
- x=5
Therefore, (5,0) works as well!
Answer:
Answer is A U B = {3,5,7}