Question

Find the distance between the pair of points. ​(19​,−8​) and ​(−14​,−23​)

Answer 1

Answer:36.25

Step-by-step explanation:distance between (x1, y1) and (x2,y2) is square root of (x2-x1)^2 + (y2-y1)^2. think of graph the distance between two points is the hypotenuse of a right angle triangle where the height is the difference of y and base is the difference of x

= square root of (19+14)^2 +(-23+8)^2= 36.25

Answer 2

Answer:

36.25 units

Step-by-step explanation:

Hi there!

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where two endpoints are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points ​(19​,−8​) and ​(−14​,−23​):

$d=\sqrt{(19-(-14))^2+(-8-(-23))^2}\\d=\sqrt{(19+14)^2+(-8+23)^2}\\d=\sqrt{(33)^2+(15)^2}\\d=\sqrt{1089+225}\\d=\sqrt{1314}\\d=36.25$

Therefore, the distance between the points is approximately 36.25 units.

I hope this helps!