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mezya [45]
2 years ago
14

Find the distance between the pair of points. ​(19​,−8​) and ​(−14​,−23​)

Mathematics
2 answers:
Olegator [25]2 years ago
8 0

Answer:36.25

Step-by-step explanation:distance between (x1, y1) and (x2,y2) is square root of (x2-x1)^2 + (y2-y1)^2. think of graph the distance between two points is the hypotenuse of a right angle triangle where the height is the difference of y and base is the difference of x

= square root of (19+14)^2 +(-23+8)^2= 36.25

Svetlanka [38]2 years ago
6 0

Answer:

36.25 units

Step-by-step explanation:

Hi there!

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where two endpoints are (x_1,y_1) and (x_2,y_2)

Plug in the given points ​(19​,−8​) and ​(−14​,−23​):

d=\sqrt{(19-(-14))^2+(-8-(-23))^2}\\d=\sqrt{(19+14)^2+(-8+23)^2}\\d=\sqrt{(33)^2+(15)^2}\\d=\sqrt{1089+225}\\d=\sqrt{1314}\\d=36.25

Therefore, the distance between the points is approximately 36.25 units.

I hope this helps!

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2 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

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