Answer:
t(s) is in rejection zone then we reject H₀.
Bad weather indeed make apples weight decrease
Step-by-step explanation:
Normal Distribution
population mean μ₀ = 9.5 ou
sample size = n = 16 then we should apply t-student table
degree of fredom df = n - 1 df = 16 - 1 df = 15
1.-Test hypothesis
H₀ null hypothesis μ₀ = 9.5
Hₐ alternative hypothesis μ₀ < 9.5
One left tail-test
2.-Confidence level 95 %
α = 0,05 and df = 15 from t-student table we get t(c) = - 1.761
3.-Compute t(s)
t(s) = [ μ - μ₀ ] /√s/n t(s) = (9.32 - 9.5 )* √16 / 0.18
t(s) = - 0.18*√16 / 0.18
t(s) = - 4
4.-Compare t(s) and t(c)
t(s) < t(c) -4 < - 1.761
Then t(s) is in the rejection zone.
5.- Decision
t(s) is in rejection zone then we reject H₀.
Farmer conclude that bad weather make apples weight decrease
<em>429 cm²</em>
- Step-by-step explanation:
<em>A(blue) =</em>
<em>= 2×6cm×10cm + 2×6cm×8cm + 8cm×10cm + (8cm×10cm - 5cm×4cm)</em>
<em>= 120cm² + 96cm² + 80cm² + 60cm²</em>
<em>= 356 cm²</em>
<em>A(green) =</em>
<em>= 4cm×5cm + 2×5cm×5cm/2 + 4cm×7cm</em>
<em>= 20cm² + 25cm² + 28cm²</em>
<em>= 73 cm²</em>
<em>A(total) =</em>
<em>= A(blue) + A(green)</em>
<em>= 356 cm² + 73 cm²</em>
<em>= 429 cm²</em>
Answer:
a shared multiple of the denominators of several fractions.
Step-by-step explanation:
~AJTHESHOOTER...
I believe it’s positive 30!
